Example 1. A well yields 1,510 GPM. The static water level is 24 ft below ground and the pumping water level is 65 ft below ground. What is the specific capacity?
- A) 23.2 GPM/ft
- B) 0.0272 GPM/ft
- C) 36.8 GPM/ft
- D) 17.0 GPM/ft
Show the answer and worked solution
Answer: C) 36.8 GPM/ft
1. Drawdown = 65 − 24 = 41 ft. 2. Specific Capacity = Well Yield ÷ Drawdown [Sheet p.1, Pumping: "Specific Capacity (GPM/Ft) = Well Yield (GPM) / Drawdown (Ft)"] = 1,510 ÷ 41 = 36.83 GPM/ft. 3. Answer: 36.8 GPM/ft (rounded to 3 significant figures).
Source: CA Exam Conversion Sheet (Revised 4/30/2026), p.1, Pumping: "Specific Capacity (GPM/Ft) = Well Yield (GPM) / Drawdown (Ft)"