Example 1. How many gallons does 900 ft of 18-inch water main hold?
- A) 5,950 gal
- B) 7,930 gal
- C) 1,590 gal
- D) 11,900 gal
Show the answer and worked solution
Answer: D) 11,900 gal
1. D = 18 ÷ 12 = 1.5 ft [12 in = 1 ft]. Keep (18 ÷ 12) in your calculator instead of the rounded value, so the answer is not thrown off. 2. Cylinder Volume (Gal) = .785 × D² × Length × 7.48 [Sheet p.1, Area and Volume: "Cylinder Volume (Gal) = .785 x D2 x Height or Length (Ft) x 7.48"]. 3. = .785 × (18 ÷ 12)² × 900 × 7.48 = 11,890 gal. 4. Answer: 11,900 gal (rounded to 3 significant figures).
Source: CA Exam Conversion Sheet (Revised 4/30/2026), p.1, Area and Volume: "Cylinder Volume (Gal) = .785 x D2 x Height or Length (Ft) x 7.48"