Example 1. The static water level in a well is 23 ft below ground. While the pump runs, the drawdown is 30 ft. How far below ground is the pumping water level?
- A) 23.0 ft
- B) 30.0 ft
- C) 7.00 ft
- D) 53.0 ft
Show the answer and worked solution
Answer: D) 53.0 ft
1. Drawdown = pumping water level − static water level (the denominator of [Sheet p.1, Pumping: "Specific Capacity (GPM/Ft) = Well Yield (GPM) / Drawdown (Ft)"]), so pumping water level = static water level + drawdown. 2. = 23 + 30 = 53 ft below ground. 3. Answer: 53.0 ft.
Source: CA Exam Conversion Sheet (Revised 4/30/2026), p.1, Pumping: "Specific Capacity (GPM/Ft) = Well Yield (GPM) / Drawdown (Ft)"