Example 1. A well pumps 2,350 GPM around the clock. How many lbs/day of chlorine are needed for a dose of 3.8 mg/L?
- A) 4.47 lbs/day
- B) 107 lbs/day
- C) 12.9 lbs/day
- D) 166 lbs/day
Show the answer and worked solution
Answer: B) 107 lbs/day
1. Flow = 2,350 ÷ 694.4 = 3.384 MGD [Sheet p.1, Units and Conversion Factors, row 29: "1 MGD = 694.4 GPM"]. 2. Gas (lbs) = MG × mg/L × 8.34 [Sheet p.1, Chlorination: "Gas (lbs) = MG x mg/L x 8.34"] = 3.384 × 3.8 × 8.34 = 107.2 lbs/day. 3. Answer: 107 lbs/day (rounded to 3 significant figures).
Source: CA Exam Conversion Sheet (Revised 4/30/2026), p.1, Units and Conversion Factors, row 29: "1 MGD = 694.4 GPM"; p.1, Chlorination: "Gas (lbs) = MG x mg/L x 8.34"