Example 1. A well's pumping water level is 247 ft below ground and its drawdown is 123 ft. What was the static water level before pumping?
- A) 1.00 ft
- B) 124 ft
- C) 62.0 ft
- D) 93.0 ft
Show the answer and worked solution
Answer: B) 124 ft
1. Drawdown = pumping water level − static water level (the denominator of [Sheet p.1, Pumping: "Specific Capacity (GPM/Ft) = Well Yield (GPM) / Drawdown (Ft)"]), so static water level = pumping water level − drawdown. 2. = 247 − 123 = 124 ft below ground. 3. Answer: 124 ft.
Source: CA Exam Conversion Sheet (Revised 4/30/2026), p.1, Pumping: "Specific Capacity (GPM/Ft) = Well Yield (GPM) / Drawdown (Ft)"