Example 1. A well yields 1,830 GPM. The static water level is 187 ft below ground and the pumping water level is 236 ft below ground. What is the specific capacity?
- A) 7.75 GPM/ft
- B) 37.3 GPM/ft
- C) 74.6 GPM/ft
- D) 9.79 GPM/ft
Show the answer and worked solution
Answer: B) 37.3 GPM/ft
1. Drawdown = 236 − 187 = 49 ft. 2. Specific Capacity = Well Yield ÷ Drawdown [Sheet p.1, Pumping: "Specific Capacity (GPM/Ft) = Well Yield (GPM) / Drawdown (Ft)"] = 1,830 ÷ 49 = 37.347 GPM/ft. 3. Answer: 37.3 GPM/ft (rounded to 3 significant figures).
Source: CA Exam Conversion Sheet (Revised 4/30/2026), p.1, Pumping: "Specific Capacity (GPM/Ft) = Well Yield (GPM) / Drawdown (Ft)"