Example 1. Before pumping, the water level in a well is 98 ft below ground. After pumping for several hours it stabilizes at 237 ft below ground. What is the drawdown?
- A) 237 ft
- B) 168 ft
- C) 335 ft
- D) 139 ft
Show the answer and worked solution
Answer: D) 139 ft
1. Drawdown = pumping water level − static water level (the denominator of [Sheet p.1, Pumping: "Specific Capacity (GPM/Ft) = Well Yield (GPM) / Drawdown (Ft)"]). 2. = 237 − 98 = 139 ft. 3. Answer: 139 ft.
Source: CA Exam Conversion Sheet (Revised 4/30/2026), p.1, Pumping: "Specific Capacity (GPM/Ft) = Well Yield (GPM) / Drawdown (Ft)"